solve for the products of the following binomials using the foil method
(2x+1) (x+1)
(8x-1) (x-2)
(-3x-3) (2x-3)
(7x+2) (-x+5)
(-3x-2) (-x-4)
Answer:
² + 3x + 1
8x² - 17x + 2
6x² + 9x - 6x + 9
6x² + 3x + 9
7x² + 33x + 10
3x² + 14x + 8
Step-by-step explanation:
Let's use the FOIL method to find the products of the given binomials:
1. (2x+1) (x+1)
FOIL: First, Outer, Inner, Last
(2x * x) + (2x * 1) + (1 * x) + (1 * 1)
2x^2 + 2x + x + 1
Simplified: 2x^2 + 3x + 1
2. (8x-1) (x-2)
FOIL:
(8x * x) + (8x * -2) + (-1 * x) + (-1 * -2)
8x^2 - 16x - x + 2
Simplified: 8x^2 - 17x + 2
3. (-3x-3) (2x-3)
FOIL:
(-3x * 2x) + (-3x * -3) + (-3 * 2x) + (-3 * -3)
-6x^2 + 9x - 6x + 9
Simplified: -6x^2 + 3x + 9
4. (7x+2) (-x+5)
FOIL:
(7x * -x) + (7x * 5) + (2 * -x) + (2 * 5)
-7x^2 + 35x - 2x + 10
Simplified: -7x^2 + 33x + 10
5. (-3x-2) (-x-4)
FOIL:
(-3x * -x) + (-3x * -4) + (-2 * -x) + (-2 * -4)
3x^2 + 12x + 2x + 8
Simplified: 3x^2 + 14x + 8
Answer:
Let's solve the products of the given binomials using the FOIL method:
1. (2x+1) (x+1):
- FOIL: First, Outer, Inner, Last
- (2x * x) + (2x * 1) + (1 * x) + (1 * 1)
- 2x^2 + 2x + x + 1
- Simplified: 2x^2 + 3x + 1
2. (8x-1) (x-2):
- FOIL: First, Outer, Inner, Last
- (8x * x) + (8x * -2) + (-1 * x) + (-1 * -2)
- 8x^2 - 16x - x + 2
- Simplified: 8x^2 - 17x + 2
3. (-3x-3) (2x-3):
- FOIL: First, Outer, Inner, Last
- (-3x * 2x) + (-3x * -3) + (-3 * 2x) + (-3 * -3)
- -6x^2 + 9x - 6x + 9
- Simplified: -6x^2 + 3x + 9
4. (7x+2) (-x+5):
- FOIL: First, Outer, Inner, Last
- (7x * -x) + (7x * 5) + (2 * -x) + (2 * 5)
- -7x^2 + 35x - 2x + 10
- Simplified: -7x^2 + 33x + 10
5. (-3x-2) (-x-4):
- FOIL: First, Outer, Inner, Last
- (-3x * -x) + (-3x * -4) + (-2 * -x) + (-2 * -4)
- 3x^2 + 12x + 2x + 8
- Simplified: 3x^2 + 14x + 8
The products of the given binomials using the FOIL method are:
1. 2x^2 + 3x + 1
2. 8x^2 - 17x + 2
3. -6x^2 + 3x + 9
4. -7x^2 + 33x + 10
5. 3x^2 + 14x + 8
Let me know if you have any other questions!